可以求出这个数的最大公因数或最小公倍数。
int gcd(int a,int b){
if(a%b==0)return b;
return gcd(b,a%b);
}
int a,b;
cin>>a>>b;
cout<<gcd(a,b);
long long gcd(long long a,long long b){
if(a%b==0)return b;
return gcd(b,a%b);
}
long long lcm(long long a,long long b){
return a*b/gcd(a,b);
}
long long a,b;
cin>>a>>b;
cout<<lcm(a,b);
#include<bits/stdc++.h>
using namespace std;
int gcd(int a,int b){
if(a%b==0)return b;
return gcd(b,a%b);
}
int main(){
int a,b;
cin>>a>>b;
cout<<gcd(a,b);
return 0;
}
#include<bits/stdc++.h>
using namespace std;
long long gcd(long long a,long long b){
if(a%b==0)return b;
return gcd(b,a%b);
}
long long lcm(long long a,long long b){
return a*b/gcd(a,b);
}
int main(){
long long a,b;
cin>>a>>b;
cout<<gcd(a,b)<<" ";
cout<<lcm(a,b);
return 0;
}
#include<bits/stdc++.h>
using namespace std;
long long gcd(long long a,long long b){
if(a%b==0)return b;
return gcd(b,a%b);
}
long long lcm(long long a,long long b){
return a*b/gcd(a,b);
}
int main(){
long long a,b,c;
cin>>a>>b>>c;
cout<<lcm(lcm(a,b),c);
return 0;
}
#include<bits/stdc++.h>
using namespace std;
int n;
int a[5000005];
int w;
int main(){
cin>>n;
cin>>a[1];
w=a[1];
for (int i=2;i<=n;i++){
cin>>a[i];
w=gcd(w,a[i]);
}
if (w%2==1) cout<<-1;
else cout<<w/2;
return 0;
}
开发者:Federico2903 & Murasame & quanac-lcx